Jordan, have you read the genetics page at
www.axolotl.org?
Here's the way I figure it works. Lets call your animal generation 2, its offspring generation 3, its parents generation 1. Generation 0 = your animals grandparents.
Generation 0 has One wildtype D/D and one leucistic (d/d) mating giving rise to a gen 1 of D/d A/?.
Generation 1: the D/d A/? and one albino (d= ?/?, a/a) or a recessive albino (D/? A/a) mate. They give rise to generation 2 (your animal) D/d OR D/D A/a (since your animal is wildtype, it must have D, and since it's not albino, it must have A, and to be recessive for albino, one of the parents had to pass on an a).
This animal is wildtype, but recessive (het) for albino (A/a) and leucistic (D/d). Unless you know the exact genotype of the previous generations, the ONLY way your animal is positively het for both albino and leucistic is if generation 3 gives rise to both leucistic an albino offspring (with a mate that is either het or dominant for leucistic or albino). So unless your animal has been bred, there's no way to prove this guy is right about it being het for either, especially both.
(Message edited by Joan on October 26, 2005)