2H3O(+) + CaCO3(s) <=> Ca(2+) + CO3(2-) + 2H30(+) <=> Ca(2+) + HCO3(-) + H30(+) + H2O <=> H2CO3 + 2H2O + Ca(2+) <=> 3H2O + CO2 + Ca(2+)
<=> 3H2O + CO2(g) + Ca(2+)
A quick glance at Keq for this system gives that it is driven by formation of CO2(g) by H3O(+).
A low pH will induce an apparent higher solubility
of CaCO3. High dissolved Calcium will produce a lower apparent solubility. High pCO2 will produce a lower apparent solubility.
In a basic system:
2OH(-) + CaCO3(s) <=> Ca(2+) + 2OH(-) + CO3(2-) <=>Ca(OH)2(s) + CO3(2-)
Since the solubility of Ca(OH)2 is a lot higher than that for CaCO3 the eq. above will be heavily shifted to the left.
If the shells dissolve it is due to a low pH not because of a high pH.
Around here at least we get CaCO3-precipitation, so shells in the tanks will absolutely not be a problem. It should be noted that the solubility of CaCO3 is dependent upon which crystal lattice is "chosen"(calcite/aragonite).
Because of different ions(Mg(2+), PO(4-)etc) is inhibiting the formation of pure calcite/aragonite lattices resulting in lower formation rates, also ions like Mg(2+) interact directly with CO3(2-) ions reducing the free concentration and enabling the oceans to be supersaturated with these ions(Ca(2+),CO3(2-)).
(Message edited by jesper on March 05, 2004)
(Message edited by jesper on March 05, 2004)