Wysper
New member
- Joined
- Jun 29, 2016
- Messages
- 197
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- Location
- Wilson, NC
- Country
- United States
- Display Name
- Crystal
I'm a little bit of a genetics freak, or at least I was in high school, so I am interested in trying to figure out the genetics for my 4 babies.
I have 4 Axolotls from the same clutch (NO I will not be breeding them to each other) that are still unsexed.
1 White Albino
1 Light Wild Type
2 Dark Wild Types
Mother = Wild Type het for leucism. (as informed by the owner)
Father = Gold Albino het for leucism (as informed by the owner)
I have done some reading and determined the following:
D = Dark / d = White
M = Non-Melanoid / m = Melanoid
A = Albino / a = Albino
AX = Non-Axanthic / ax = Axanthic
Phenotype = what they look like
Genotype = genetic makeup
Heterozygous = different genetics ex: D/d
Homozygous = same genetics ex: d/d
With this information I have determined the following:
Mother = D/d A/a M/M AX/ax
Father = D/d a/a M/M AX/ax
Since they are both het for leucism I determined that they would carry the d gene to be able to produce that.
Since there were both gold albino and albino babies produced in the clutch I determined that the mother would have to carry the a gene.
All of my 4 have iridophores so I am going to assume that both parents carry M/M genes.
One of my wild types has a pronounced coloration of red and yellow along her sides, with red/pink gills, so I am thinking both parents would be AX/ax to produce that coloration with ax/ax.
Thoughts comments suggestions?
I have 4 Axolotls from the same clutch (NO I will not be breeding them to each other) that are still unsexed.
1 White Albino
1 Light Wild Type
2 Dark Wild Types
Mother = Wild Type het for leucism. (as informed by the owner)
Father = Gold Albino het for leucism (as informed by the owner)
I have done some reading and determined the following:
D = Dark / d = White
M = Non-Melanoid / m = Melanoid
A = Albino / a = Albino
AX = Non-Axanthic / ax = Axanthic
Phenotype = what they look like
Genotype = genetic makeup
Heterozygous = different genetics ex: D/d
Homozygous = same genetics ex: d/d
With this information I have determined the following:
Mother = D/d A/a M/M AX/ax
Father = D/d a/a M/M AX/ax
Since they are both het for leucism I determined that they would carry the d gene to be able to produce that.
Since there were both gold albino and albino babies produced in the clutch I determined that the mother would have to carry the a gene.
All of my 4 have iridophores so I am going to assume that both parents carry M/M genes.
One of my wild types has a pronounced coloration of red and yellow along her sides, with red/pink gills, so I am thinking both parents would be AX/ax to produce that coloration with ax/ax.
Thoughts comments suggestions?