Axolotl Genetics Discussion

Wysper

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I'm a little bit of a genetics freak, or at least I was in high school, so I am interested in trying to figure out the genetics for my 4 babies.

I have 4 Axolotls from the same clutch (NO I will not be breeding them to each other) that are still unsexed.

1 White Albino
1 Light Wild Type
2 Dark Wild Types

Mother = Wild Type het for leucism. (as informed by the owner)
Father = Gold Albino het for leucism (as informed by the owner)

I have done some reading and determined the following:

D = Dark / d = White
M = Non-Melanoid / m = Melanoid
A = Albino / a = Albino
AX = Non-Axanthic / ax = Axanthic

Phenotype = what they look like
Genotype = genetic makeup
Heterozygous = different genetics ex: D/d
Homozygous = same genetics ex: d/d

With this information I have determined the following:

Mother = D/d A/a M/M AX/ax
Father = D/d a/a M/M AX/ax

Since they are both het for leucism I determined that they would carry the d gene to be able to produce that.

Since there were both gold albino and albino babies produced in the clutch I determined that the mother would have to carry the a gene.

All of my 4 have iridophores so I am going to assume that both parents carry M/M genes.

One of my wild types has a pronounced coloration of red and yellow along her sides, with red/pink gills, so I am thinking both parents would be AX/ax to produce that coloration with ax/ax.


Thoughts comments suggestions?
 

holdonbaby

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I wish I remembered more about genetics. I only very briefly covered in highschool/college bio. If I remember correctly, the capital letters indicate a dominate gene and the lower case indicate recessive. Is that correct? Also, I'm assuming that "clutch" means breeding pair? I've never heard that term before.
 

Wysper

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Yes, capital letter would represent a dominate gene.

Clutch is used to say a single bunch of eggs laid, making all siblings. I am not quite sure what that is called in axolotls. Clutch is commonly used to say a single sac of eggs from a snail.

With my example, it would kind of look like this:


Mother = D/d A/a M/M AX/ax
Father = D/d a/a M/M AX/ax

D d
D D/D D/d
d D/d d/d
25% of offspring would be D/D making them wild type.
50% of offspring would be D/d making them wild type het for leucism.
25% of offspring would be d/d making them leucistic.

A a
a A/a a/a
a A/a a/a
50% of offspring would be albino.
50% of offspring would be Non-albino het for albinism.


M M
M M/M M/M
M M/M M/M
100% of offspring would be Non-Melanoid.

AX ax
AX AX/AX AX/ax
ax AX/ax ax/ax
25% of offspring would be Non-Axanthic.
50% of offspring would be Non-Axanthic, het for Axanthic.
25% of offspring would be Axanthic.
 
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